Toluene reacts with excess of Cl_2 in the pre | vedclass

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Question

(B) $1$. Toluene $(C_6H_5CH_3)$ reacts with excess $Cl_2$ in the presence of sunlight (free radical substitution) to form benzotrichloride $(C_6H_5CCl

Vedclass · Accepted Answer

Sodium benzoate

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(B) $1$. Toluene $(C_6H_5CH_3)$ reacts with excess $Cl_2$ in the presence of sunlight (free radical substitution) to form benzotrichloride $(C_6H_5CCl_3)$.$2$. Benzotrichloride on hydrolysis gives benzoic acid $(C_6H_5COOH)$.$3$. Benzoic acid reacts with $NaOH$ (an acid-base reaction) to form sodium benzoate $(C_6H_5COONa)$.Therefore,the final product is sodium benzoate.

Toluene reacts with excess of $Cl_2$ in the presence of sunlight to give a product which on hydrolysis followed by reaction with $NaOH$ gives:

Similar Questions

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