Total number of compounds / ions which have a | vedclass

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(C) $1$. $CO_3^{2-}$: It has resonance,so all three $C-O$ bond lengths are equal. Thus,at least two are same. (Yes)$2$. $HCOOH$: It has one $C=O$ bond

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$3$

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(C) $1$. $CO_3^{2-}$: It has resonance,so all three $C-O$ bond lengths are equal. Thus,at least two are same. (Yes)$2$. $HCOOH$: It has one $C=O$ bond and one $C-OH$ bond. The bond lengths are different. However,in the resonance hybrid,the $C-O$ bonds have partial double bond character,but they are not identical to each other. (No)$3$. $S_2O_3^{2-}$: The structure has two types of $S-O$ bonds: two terminal $S=O$ bonds and two $S-O$ single bonds. The two $S=O$ bonds are equivalent,and the two $S-O$ bonds are equivalent. Thus,at least two bond lengths are same. (Yes)$4$. $NO_2^{-}$: It has resonance,so both $N-O$ bond lengths are equal. Thus,at least two are same. (Yes)Therefore,$CO_3^{2-}, S_2O_3^{2-}$,and $NO_2^{-}$ satisfy the condition. The total count is $3$.

Total number of compounds / ions which have at least two bond lengths same out of $CO_3^{2-}, HCOOH, S_2O_3^{2-}, NO_2^{-}$

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