The total number of elements in the 10^{th} p | vedclass

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(C) For a period $n$,the number of subshells present is given by the formula: $	ext{Number of subshells} = \frac{n}{2} + 1$ (for even $n$).For $n = 1

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$72$

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(C) For a period $n$,the number of subshells present is given by the formula: $	ext{Number of subshells} = \frac{n}{2} + 1$ (for even $n$).For $n = 10$,the number of subshells is $\frac{10}{2} + 1 = 6$.These subshells are $s, p, d, f, g,$ and $h$.The maximum number of electrons (and thus elements) in these subshells are:$s = 2$$p = 6$$d = 10$$f = 14$$g = 18$$h = 22$Total elements $= 2 + 6 + 10 + 14 + 18 + 22 = 72$.

The total number of elements in the $10^{th}$ period of the periodic table will be:

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