The total number of stereoisomers possible fo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The compound is $1,3,5$-tribromocyclohexane. It has three chiral centers at positions $1, 3,$ and $5$. Due to the symmetry of the cyclohexane ring

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) The compound is $1,3,5$-tribromocyclohexane. It has three chiral centers at positions $1, 3,$ and $5$. Due to the symmetry of the cyclohexane ring,we can have different spatial arrangements of the bromine atoms (cis/trans). The possible stereoisomers are: $1$. All three $Br$ atoms are on the same side (all-cis isomer),which has a plane of symmetry (meso compound). $2$. Two $Br$ atoms are on one side and one $Br$ atom is on the opposite side (cis-cis-trans isomer). This exists as a pair of enantiomers. $3$. One $Br$ atom is on one side and two $Br$ atoms are on the opposite side (trans-trans-cis isomer). This is identical to the previous case due to symmetry. Thus,there are $3$ stereoisomers: one meso form and one pair of enantiomers $(1 + 2 = 3)$.

The total number of stereoisomers possible for the given compound $1,3,5$-tribromocyclohexane is:

Similar Questions

The binaphthol $(Bnp)$ is

The number of chiral centres present in $[B]$ is

Which of the following statements is incorrect?

Which of the following compounds is achiral?

Which of the following molecules is not chiral?

Vedclass Test Series

Exam Paper Generator

Online Exam Module