Treatment of a $2^{\circ} \text{ alcohol}$ with $CrO_3/H_2SO_4$ yields a/an

  • A
    aldehyde
  • B
    carboxylic acid
  • C
    ester
  • D
    ketone

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Correct order of reactivity of the given alcohols towards the substitution with $(NaBr + H_2SO_4)$ is:

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