Treatment of propionaldehyde with dilute NaOH | vedclass

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Question

(B) Propionaldehyde $(CH_3CH_2CHO)$ contains $\alpha$-hydrogens,so it undergoes an aldol condensation reaction in the presence of a dilute base like $

Vedclass · Accepted Answer

$CH_3CH_2CH(OH)CH(CH_3)CHO$

Vedclass · Answer

(B) Propionaldehyde $(CH_3CH_2CHO)$ contains $\alpha$-hydrogens,so it undergoes an aldol condensation reaction in the presence of a dilute base like $NaOH$.The reaction proceeds as follows:$CH_3CH_2CHO + CH_3CH_2CHO \xrightarrow{dil. NaOH} CH_3CH_2CH(OH)CH(CH_3)CHO$The product formed is $3$-hydroxy-$2$-methylpentanal.

Treatment of propionaldehyde with dilute $NaOH$ solution gives:

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