Trioxalato aluminate (III) and tetrafluoro-bo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Trioxalato aluminate $(III)$: The central metal is $Al$ with an oxidation state of $+3$. The oxalate ion $(C_2O_4^{2-})$ is a bidentate ligand wit

Vedclass · Accepted Answer

$[Al(C_2O_4)_3]^{3-} , [BF_4]^{-}$

Vedclass · Answer

(C) Trioxalato aluminate $(III)$: The central metal is $Al$ with an oxidation state of $+3$. The oxalate ion $(C_2O_4^{2-})$ is a bidentate ligand with a charge of $-2$. The coordination entity is $[Al(C_2O_4)_3]^{x}$.Calculating the charge: $x = +3 + 3(-2) = +3 - 6 = -3$. Thus,the ion is $[Al(C_2O_4)_3]^{3-}$.Tetrafluoro borate $(III)$: The central atom is $B$ with an oxidation state of $+3$. It is bonded to $4$ fluoride ions $(F^-)$,each with a charge of $-1$. The coordination entity is $[BF_4]^{y}$.Calculating the charge: $y = +3 + 4(-1) = +3 - 4 = -1$. Thus,the ion is $[BF_4]^{-}$.

Trioxalato aluminate $(III)$ and tetrafluoro-borate $(III)$ ions are :

Similar Questions

Define the following terms:
$1$. Coordination entity
$2$. Central metal ion

$A$ complex compound of $Co^{3+}$ with molecular formula $CoCl_{x} \cdot yNH_3$ gives a total of $3$ ions when dissolved in water. How many $Cl^{-}$ ions satisfy both primary and secondary valencies in this complex?

What is the number of $N$ atoms present in $EDTA$?

Which coordination compound from the following has a net negative charge on the complex ion?

Potassium cyanide is made alkaline with $NaOH$ and boiled with thiosulphate ions. The solution is cooled and acidified with $HCl$ and this solution with iron $(III)$ chloride produces :-

Vedclass Test Series

Exam Paper Generator

Online Exam Module