Two balanced dice are rolled. Find the probab | vedclass

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(B) When two dice are rolled,the total number of possible outcomes is $6 	imes 6 = 36$.We need to find the probability that the sum $S$ of the number

Vedclass · Accepted Answer

$\frac{4}{9}$

Vedclass · Answer

(B) When two dice are rolled,the total number of possible outcomes is $6 	imes 6 = 36$.We need to find the probability that the sum $S$ of the numbers on the two dice lies between $5$ and $9$,which means $5 This implies the sum $S$ can be $6, 7,$ or $8$.- For $S = 6$,the possible outcomes are $(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)$,which are $5$ outcomes.- For $S = 7$,the possible outcomes are $(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)$,which are $6$ outcomes.- For $S = 8$,the possible outcomes are $(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)$,which are $5$ outcomes.Total favorable outcomes = $5 + 6 + 5 = 16$.Probability = $\frac{	ext{Favorable outcomes}}{	ext{Total outcomes}} = \frac{16}{36} = \frac{4}{9}$.

Two balanced dice are rolled. Find the probability that the sum of numbers on two dice lies between $5$ and $9$.

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