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Question

(A) When two balanced dice are rolled simultaneously,the total number of possible outcomes is $6 	imes 6 = 36$.The favorable outcomes where the same

Vedclass · Accepted Answer

$\frac{1}{6}$

Vedclass · Answer

(A) When two balanced dice are rolled simultaneously,the total number of possible outcomes is $6 	imes 6 = 36$.The favorable outcomes where the same number appears on both dice are $(1, 1), (2, 2), (3, 3), (4, 4), (5, 5),$ and $(6, 6)$.Thus,the number of favorable outcomes is $m = 6$.The probability of an event is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.Therefore,the required probability $= \frac{m}{n} = \frac{6}{36} = \frac{1}{6}$.

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