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(A) When two balanced dice are rolled simultaneously,the total number of possible outcomes is $6 	imes 6 = 36$.Let $E$ be the event that the sum of t

Vedclass · Accepted Answer

$\frac{1}{36}$

Vedclass · Answer

(A) When two balanced dice are rolled simultaneously,the total number of possible outcomes is $6 	imes 6 = 36$.Let $E$ be the event that the sum of the numbers on the two dice is $2$.The only outcome that results in a sum of $2$ is $(1, 1)$.Therefore,the number of favourable outcomes is $m = 1$.The probability of the event $E$ is given by the formula: $P(E) = \frac{	ext{Number of favourable outcomes}}{	ext{Total number of possible outcomes}}$.Thus,$P(E) = \frac{1}{36}$.

Two balanced dice are rolled simultaneously. Then,the probability that the sum of numbers on the dice is $2$ is ............

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