Two billiard balls each of mass 0.05; kg movi | vedclass

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(B) Mass of each ball $m = 0.05\; kg$.Initial velocity of ball $1$ is $v_1 = 6\; m/s$ and ball $2$ is $v_2 = -6\; m/s$.Initial momentum of ball $1$ is

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$0.6$

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(B) Mass of each ball $m = 0.05\; kg$.Initial velocity of ball $1$ is $v_1 = 6\; m/s$ and ball $2$ is $v_2 = -6\; m/s$.Initial momentum of ball $1$ is $p_{i1} = m 	imes v_1 = 0.05 	imes 6 = 0.3\; kg\; m/s$.After collision,they rebound with the same speed,so final velocity of ball $1$ is $v_{f1} = -6\; m/s$.Final momentum of ball $1$ is $p_{f1} = m 	imes v_{f1} = 0.05 	imes (-6) = -0.3\; kg\; m/s$.Impulse imparted to ball $1$ is the change in its momentum: $J = p_{f1} - p_{i1} = -0.3 - 0.3 = -0.6\; Ns$.The magnitude of the impulse imparted to each ball is $0.6\; Ns$.

Two billiard balls each of mass $0.05\; kg$ moving in opposite directions with speed $6\; m/s$ collide and rebound with the same speed. What is the impulse imparted to each ball due to the other (in $; Ns$)?

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