Two blocks of 7 kg and 5 kg are connected b | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The total mass of the system is $M = 7 \ kg + 4 \ kg + 5 \ kg = 16 \ kg$. Applying Newton's second law to the whole system: $F - Mg = Ma$. $200 -

Vedclass · Accepted Answer

$112.5$

Vedclass · Answer

(B) The total mass of the system is $M = 7 \ kg + 4 \ kg + 5 \ kg = 16 \ kg$. Applying Newton's second law to the whole system: $F - Mg = Ma$. $200 - 16 	imes 10 = 16 	imes a$. $200 - 160 = 16a$,which gives $40 = 16a$. So,the acceleration is $a = \frac{40}{16} = 2.5 \ m/s^2$. To find the tension $T$ at point $P$ (top of the rope),we consider the system consisting of the $5 \ kg$ block and the $4 \ kg$ rope. The total mass below point $P$ is $m' = 5 \ kg + 4 \ kg = 9 \ kg$. Applying Newton's second law to this subsystem: $T - m'g = m'a$. $T - 9 	imes 10 = 9 	imes 2.5$. $T - 90 = 22.5$. $T = 90 + 22.5 = 112.5 \ N$.

Two blocks of $7 \ kg$ and $5 \ kg$ are connected by a heavy rope of mass $4 \ kg$. An upward force of $200 \ N$ is applied as shown in the diagram. The tension at the top end of the heavy rope at point $P$ is: $(g = 10 \ m/s^2)$ (in $N$)

Similar Questions

If $g(x) = \int_0^x \cos^4 t \, dt$,then $g(x + \pi)$ equals

What is obtained when gypsum is heated at $300\,^oC$?

The perimeter of the triangle with vertices at $(1,0,0), (0,1,0)$ and $(0,0,1)$ is

Marchantia is an example of.

The number of atoms/molecules contained in one face-centred cubic $(FCC)$ unit cell of a monoatomic substance is

Vedclass Test Series

Exam Paper Generator

Online Exam Module