Two bodies A and B start from rest from the s | vedclass

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(C) Given:Acceleration $a = 2\,m/s^2$.Body $A$ starts at $t = 0$ and travels for $t_A = 2\,s$ (one second after $B$ starts,which is $1+1=2\,s$ total).

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$3$

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(C) Given:Acceleration $a = 2\,m/s^2$.Body $A$ starts at $t = 0$ and travels for $t_A = 2\,s$ (one second after $B$ starts,which is $1+1=2\,s$ total).Body $B$ starts at $t = 1\,s$ and travels for $t_B = 1\,s$ (at the end of the next second).Using the equation of motion $s = ut + \frac{1}{2}at^2$,where $u = 0$:Distance traveled by $A$ in $2\,s$ is $s_A = \frac{1}{2} 	imes 2 	imes (2)^2 = 4\,m$.Distance traveled by $B$ in $1\,s$ is $s_B = \frac{1}{2} 	imes 2 	imes (1)^2 = 1\,m$.The separation between the two bodies is $s_A - s_B = 4\,m - 1\,m = 3\,m$.

Two bodies $A$ and $B$ start from rest from the same point with a uniform acceleration of $2\,m/s^2$. If $B$ starts one second later,then the two bodies are separated,at the end of the next second,by $.............\,m$.

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