Two bodies of masses 0.1, kg and 0.4, kg move | vedclass

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(D) According to the law of conservation of linear momentum,the total momentum before collision is equal to the total momentum after collision.$m_{1}

Vedclass · Accepted Answer

$1.2$

Vedclass · Answer

(D) According to the law of conservation of linear momentum,the total momentum before collision is equal to the total momentum after collision.$m_{1} v_{1} + m_{2} v_{2} = (m_{1} + m_{2}) v$Where $v$ is the common velocity of the two bodies after they stick together.Given:$m_{1} = 0.1\, kg$,$m_{2} = 0.4\, kg$$v_{1} = 1\, m/s$,$v_{2} = -0.1\, m/s$ (since they move towards each other,we take opposite directions).Substituting the values:$(0.1 	imes 1) + (0.4 	imes -0.1) = (0.1 + 0.4) v$$0.1 - 0.04 = 0.5 v$$0.06 = 0.5 v$$v = \frac{0.06}{0.5} = 0.12\, m/s$Distance covered in $t = 10\, s$ is:$d = v 	imes t = 0.12\, m/s 	imes 10\, s = 1.2\, m$.

Two bodies of masses $0.1\, kg$ and $0.4\, kg$ move towards each other with the velocities $1\, m/s$ and $0.1\, m/s$ respectively. After collision they stick together. In $10\, s$ the combined mass travels ............... $m$.

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