Two bodies of masses 1 ,g and 4 ,g are moving | vedclass

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(C) Given: Masses $m_1 = 1 \,g$ and $m_2 = 4 \,g$. Kinetic energies are equal, $K_1 = K_2$.We know the relation between kinetic energy $K$ and linear

Vedclass · Accepted Answer

$1:2$

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(C) Given: Masses $m_1 = 1 \,g$ and $m_2 = 4 \,g$. Kinetic energies are equal, $K_1 = K_2$.We know the relation between kinetic energy $K$ and linear momentum $p$ is $K = \frac{p^2}{2m}$, which implies $p = \sqrt{2mK}$.Since $K_1 = K_2$, the ratio of momenta is $\frac{p_1}{p_2} = \frac{\sqrt{2m_1K_1}}{\sqrt{2m_2K_2}} = \sqrt{\frac{m_1}{m_2}}$.Substituting the values: $\frac{p_1}{p_2} = \sqrt{\frac{1}{4}} = \frac{1}{2}$.Thus, the ratio of their linear momenta is $1:2$.

Two bodies of masses $1 \,g$ and $4 \,g$ are moving with equal kinetic energies. The ratio of the magnitudes of their linear momenta is

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