Two bolts,two nuts,and three needles are in a box. Two parts are chosen at random from the box. What is the probability that one is a bolt and one is a needle?
- A$\frac{2}{21}$
- B$\frac{4}{21}$
- C$\frac{6}{21}$
- D$\frac{12}{21}$
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If an unbiased dice is rolled thrice,then the probability of getting a greater number in the $i^{\text{th}}$ roll than the number obtained in the $(i-1)^{\text{th}}$ roll,for $i=2, 3$,is equal to: (in $/54$)
$A$ bag contains $6$ red, $2$ white and $8$ blue balls. Three balls are drawn at random from the bag. Match the items of List-$I$ with those of List-$II$.
$A$. Probability that none of the balls is white $I$. $\frac{1}{70}$ $B$. Probability of getting $2$ white and $1$ blue ball $II$. $\frac{6}{35}$ $C$. Probability of getting $2$ blue and $1$ white ball $III$. $\frac{13}{20}$ $D$. Probability of getting $1$ red, $1$ white and $1$ blue ball $IV$. $\frac{1}{10}$
| $A$. Probability that none of the balls is white | $I$. $\frac{1}{70}$ |
| $B$. Probability of getting $2$ white and $1$ blue ball | $II$. $\frac{6}{35}$ |
| $C$. Probability of getting $2$ blue and $1$ white ball | $III$. $\frac{13}{20}$ |
| $D$. Probability of getting $1$ red, $1$ white and $1$ blue ball | $IV$. $\frac{1}{10}$ |
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