Two bubbles A and B (r_A r_B) are joined th | vedclass

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(A) The excess pressure inside a soap bubble is given by $P = \frac{4T}{r}$,where $T$ is the surface tension and $r$ is the radius of the bubble.Since

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The size of $A$ will increase

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(A) The excess pressure inside a soap bubble is given by $P = \frac{4T}{r}$,where $T$ is the surface tension and $r$ is the radius of the bubble.Since $r_A > r_B$,the pressure inside bubble $A$ $(P_A)$ is less than the pressure inside bubble $B$ $(P_B)$ because $P \propto \frac{1}{r}$.When the two bubbles are connected by a narrow tube,air flows from the region of higher pressure to the region of lower pressure.Therefore,air flows from bubble $B$ to bubble $A$.As a result,the size of bubble $B$ decreases and the size of bubble $A$ increases.

Two bubbles $A$ and $B$ $(r_A > r_B)$ are joined through a narrow tube. Then

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