Two capacitors $C_1 = 3 \mu F$ and $C_2 = 2 \mu F$ are connected in series across a d.c. source of $100 \ V$. The ratio of the potential across $C_2$ to $C_1$ is

Find the equivalent capacitance between two points $A$ and $B$ for the given circuit. (Capacitance of each capacitor is $C = 3 \mu F$.) (in $\mu F$)

Three capacitors $C_1$,$C_2$,and $C_3$ are connected in parallel,and their equivalent capacitance is $12$ units. Given $C_1 \cdot C_2 \cdot C_3 = 48$ units. When $C_1$ and $C_2$ are connected in parallel,their equivalent capacitance is $6$ units. Find the individual capacitances $C_1, C_2, C_3$.

When three capacitors of equal capacities are connected in parallel and one of the same capacitor is connected in series with this combination,the resultant capacity is $3.75 \mu F$. The capacity of each capacitor is: (in $\mu F$)

Seven capacitors,each of capacitance $2\,\mu F$,are to be connected in a configuration to obtain an effective capacitance of $\left( \frac{6}{13} \right)\,\mu F$. Which of the combinations,shown in figures below,will achieve the desired value?

In the adjoining figure, the potential difference between $X$ and $Y$ is $60 \ V$. The potential difference between the points $M$ and $N$ will be: (in $V$)