Two capacitors, C_1 = 2 text{ mF} and C_2 = 8 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) When capacitors are connected in series, the equivalent capacitance $C_{net}$ is given by:$C_{net} = \frac{C_1 	imes C_2}{C_1 + C_2} = \frac{2

Vedclass · Accepted Answer

The charge on each capacitor is $480 	imes 10^{-3} 	ext{ C}$

Vedclass · Answer

(A) When capacitors are connected in series, the equivalent capacitance $C_{net}$ is given by:$C_{net} = \frac{C_1 	imes C_2}{C_1 + C_2} = \frac{2 	imes 8}{2 + 8} = 1.6 	ext{ mF} = 1.6 	imes 10^{-3} 	ext{ F}$.The total charge $Q$ supplied by the source is:$Q = C_{net} 	imes V = 1.6 	imes 10^{-3} 	imes 300 = 0.48 	ext{ C} = 480 	imes 10^{-3} 	ext{ C}$.In a series circuit, the charge on each capacitor is the same, so $Q_1 = Q_2 = 480 	imes 10^{-3} 	ext{ C}$.The potential difference across $C_1$ is $V_1 = \frac{Q}{C_1} = \frac{480 	imes 10^{-3}}{2 	imes 10^{-3}} = 240 	ext{ V}$.The potential difference across $C_2$ is $V_2 = \frac{Q}{C_2} = \frac{480 	imes 10^{-3}}{8 	imes 10^{-3}} = 60 	ext{ V}$.The total energy stored is $U = \frac{1}{2} C_{net} V^2 = \frac{1}{2} 	imes 1.6 	imes 10^{-3} 	imes (300)^2 = 0.8 	imes 10^{-3} 	imes 90000 = 72 	ext{ J}$.

Two capacitors, $C_1 = 2 \text{ mF}$ and $C_2 = 8 \text{ mF}$, are connected in series across a $300 \text{ V}$ source. Then:

Similar Questions

In the given circuit,a charge of $+80 \mu C$ is given to the upper plate of a $4 \mu F$ capacitor. At steady state,the charge on the upper plate of the $3 \mu F$ capacitor is (in $\mu C$)

Find the equivalent capacitance across points $A$ and $B$.

Four identical capacitors are connected in series with a battery of $emf$ $10 \ V$. Point $X$ is grounded. Find the potential at point $A$ in $V$.

How will you connect four capacitors,each of capacitance $4 \mu F$,to obtain an equivalent capacitance of $1.6 \mu F$?

Three capacitors each of capacitance $C$ and of breakdown voltage $V$ are joined in series. The capacitance and breakdown voltage of the combination will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module