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(B) There are $52$ cards in a deck,and $4$ of them are aces.The probability of drawing the first ace is $P(A_1) = \frac{4}{52}$.Since the first card i

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$\frac{4}{52} 	imes \frac{3}{51}$

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(B) There are $52$ cards in a deck,and $4$ of them are aces.The probability of drawing the first ace is $P(A_1) = \frac{4}{52}$.Since the first card is not replaced,there are now $51$ cards remaining in the deck,and only $3$ of them are aces.The probability of drawing the second ace given that the first was an ace is $P(A_2|A_1) = \frac{3}{51}$.The total probability of drawing two aces is $P(A_1 \cap A_2) = P(A_1) 	imes P(A_2|A_1) = \frac{4}{52} 	imes \frac{3}{51}$.

Two cards are drawn from a well-shuffled ordinary deck of $52$ cards. What is the probability that they are both aces if the first card is not replaced?

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