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(B) Given:Speed of source (car $A$),$v_s = 36 \, km/hr = 36 	imes \frac{5}{18} = 10 \, m/s$.Speed of observer (car $B$),$v_o = 54 \, km/hr = 54 	ime

Vedclass · Accepted Answer

$984.84$

Vedclass · Answer

(B) Given:Speed of source (car $A$),$v_s = 36 \, km/hr = 36 	imes \frac{5}{18} = 10 \, m/s$.Speed of observer (car $B$),$v_o = 54 \, km/hr = 54 	imes \frac{5}{18} = 15 \, m/s$.Frequency of source,$n_0 = 1000 \, Hz$.Speed of sound,$v = 340 \, m/s$.Using the Doppler effect formula for frequency $n'$ received by the observer:$n' = n_0 \left( \frac{v - v_o}{v - v_s} ight)$Here,the observer is moving away from the source (negative sign in numerator) and the source is moving towards the observer (negative sign in denominator).$n' = 1000 \left( \frac{340 - 15}{340 - 10} ight)$$n' = 1000 \left( \frac{325}{330} ight)$$n' = 1000 	imes 0.98484 = 984.84 \, Hz$.

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