Two cars of masses m_{1} and m_{2} are moving | vedclass

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(D) The centripetal force $F$ acting on a body of mass $m$ moving in a circle of radius $r$ with angular velocity $\omega$ is given by $F = m r \omega

Vedclass · Accepted Answer

$m_{1} r_{1}: m_{2} r_{2}$

Vedclass · Answer

(D) The centripetal force $F$ acting on a body of mass $m$ moving in a circle of radius $r$ with angular velocity $\omega$ is given by $F = m r \omega^2$.Since both cars complete their circles in the same time $t$,their angular velocities are equal: $\omega = \frac{2\pi}{t}$.Therefore,the ratio of the centripetal forces $F_{1}$ and $F_{2}$ is:$\frac{F_{1}}{F_{2}} = \frac{m_{1} r_{1} \omega^2}{m_{2} r_{2} \omega^2} = \frac{m_{1} r_{1}}{m_{2} r_{2}}$.Thus,the ratio is $m_{1} r_{1} : m_{2} r_{2}$.

Two cars of masses $m_{1}$ and $m_{2}$ are moving in circles of radii $r_{1}$ and $r_{2}$ respectively. Their speeds are such that they make complete circles in the same time $t$. The ratio of their centripetal force is

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