Two charges are at a distance d apart. If a c | vedclass

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(C) The force between two point charges $q_1$ and $q_2$ separated by a distance $d$ in a vacuum is given by $F = \frac{1}{4\pi\epsilon_0} \frac{q_1 q_

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$0$

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(C) The force between two point charges $q_1$ and $q_2$ separated by a distance $d$ in a vacuum is given by $F = \frac{1}{4\pi\epsilon_0} \frac{q_1 q_2}{d^2}$.When a conducting plate (like copper) of thickness $t$ is placed between the charges,the effective distance between the charges is reduced. The effective distance $d_{eff}$ is given by $d_{eff} = (d - t) + t\sqrt{K}$,where $K$ is the dielectric constant.For a conductor,the dielectric constant $K = \infty$.Therefore,$d_{eff} = (d - t) + t\sqrt{\infty} = \infty$.Since the force $F \propto \frac{1}{d_{eff}^2}$,as $d_{eff} 	o \infty$,the force $F 	o 0$.

Two charges are at a distance $d$ apart. If a copper plate (conducting medium) of thickness $d/2$ is placed between them,the effective force will be

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