Two coaxial solenoids are made by winding thi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The formula for the mutual inductance $M$ of two coaxial solenoids is given by $M = \frac{\mu_0 N_1 N_2 A}{\ell}$.Given values are:$A = 10 \ cm^2

Vedclass · Accepted Answer

$2.4\pi 	imes 10^{-4} \ H$

Vedclass · Answer

(A) The formula for the mutual inductance $M$ of two coaxial solenoids is given by $M = \frac{\mu_0 N_1 N_2 A}{\ell}$.Given values are:$A = 10 \ cm^2 = 10 	imes 10^{-4} \ m^2 = 10^{-3} \ m^2$$\ell = 20 \ cm = 0.2 \ m$$N_1 = 300$$N_2 = 400$$\mu_0 = 4\pi 	imes 10^{-7} \ T \ m \ A^{-1}$Substituting these values into the formula:$M = \frac{(4\pi 	imes 10^{-7}) 	imes 300 	imes 400 	imes 10^{-3}}{0.2}$$M = \frac{4\pi 	imes 10^{-7} 	imes 120000 	imes 10^{-3}}{0.2}$$M = \frac{4\pi 	imes 10^{-7} 	imes 120}{0.2}$$M = 4\pi 	imes 10^{-7} 	imes 600$$M = 2400\pi 	imes 10^{-7} \ H = 2.4\pi 	imes 10^{-4} \ H$.

Similar Questions

Two coils of self-inductance $25 \ mH$ and $9 \ mH$ are placed close together such that the effective flux in one coil is completely linked with the other. The mutual inductance between these coils is (in $mH$)

The mutual inductance of two coils is $8 \ mH$. The current in one coil changes according to the equation $I = 12 \sin 100t$,where $I$ is in ampere and $t$ is time in second. The maximum value of emf induced in the second coil is (in $V$)

Two coils of self-inductances $2\, mH$ and $8\, mH$ are placed so close together that the effective flux in one coil is completely linked with the other. The mutual inductance between these coils is......$mH$.

Two circular coils of radii $r_1$ and $r_2$ $(r_1 \ll r_2)$ are placed coaxially with their centers coinciding. The mutual inductance of the arrangement is

The coefficient of mutual induction is $2 \ H$ and the induced e.m.f. across the secondary coil is $2 \ kV$. The current in the primary coil is reduced from $6 \ A$ to $3 \ A$. The time required for the change of current is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module