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(C) Given: The phase difference between two coherent plane waves is $\phi = 60^{\circ}$.The resultant intensity $I_R$ of two coherent waves is given b

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$3I$

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(C) Given: The phase difference between two coherent plane waves is $\phi = 60^{\circ}$.The resultant intensity $I_R$ of two coherent waves is given by the formula: $I_R = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$.Since the intensities of both waves are identical, we have $I_1 = I_2 = I$.Substituting these values into the formula:$I_R = I + I + 2\sqrt{I \cdot I} \cos 60^{\circ}$$I_R = 2I + 2I \cos 60^{\circ}$Since $\cos 60^{\circ} = \frac{1}{2}$, we get:$I_R = 2I + 2I \left( \frac{1}{2} \right)$$I_R = 2I + I = 3I$.Therefore, the resulting intensity is $3I$.

Two coherent plane waves of identical frequency, polarization, and intensity $I$ interfere at a point where they differ in phase by $60^{\circ}$. What is the resulting intensity?

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