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(B) According to the principle of mutual induction,the magnetic flux $\phi$ linked with a coil is proportional to the current $I$ flowing through the

Vedclass · Accepted Answer

$6.67 	imes 10^{-4}\, Wb$

Vedclass · Answer

(B) According to the principle of mutual induction,the magnetic flux $\phi$ linked with a coil is proportional to the current $I$ flowing through the other coil,given by $\phi = MI$,where $M$ is the coefficient of mutual induction.For the first case,when current $I_P = 3\, A$ flows through coil $P$,the flux through coil $Q$ is $\phi_Q = 10^{-3}\, Wb$.Using the relation $\phi_Q = M I_P$:$10^{-3} = M 	imes 3$$M = \frac{1}{3} 	imes 10^{-3}\, H$For the second case,when current $I_Q = 2\, A$ flows through coil $Q$,the flux through coil $P$ is $\phi_P = M I_Q$.Since the coefficient of mutual induction $M$ is the same for both cases:$\phi_P = (\frac{1}{3} 	imes 10^{-3}) 	imes 2$$\phi_P = \frac{2}{3} 	imes 10^{-3}\, Wb$$\phi_P = 0.666... 	imes 10^{-3}\, Wb = 6.67 	imes 10^{-4}\, Wb$.

Two coils $P$ and $Q$ are separated by some distance. When a current of $3\, A$ flows through coil $P$,a magnetic flux of $10^{-3}\, Wb$ passes through $Q$. No current is passed through $Q$. When no current passes through $P$ and a current of $2\, A$ passes through $Q$,the flux through $P$ is:

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