Two compounds with molecular formula C_4H_6 a | vedclass

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(A) The molecular formula $C_4H_6$ corresponds to the general formula $C_nH_{2n-2}$,which indicates the presence of an alkyne or a diene.Terminal alky

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$But-1-yne$ and $But-2-yne$

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(A) The molecular formula $C_4H_6$ corresponds to the general formula $C_nH_{2n-2}$,which indicates the presence of an alkyne or a diene.Terminal alkynes (alkynes with a hydrogen atom attached to the $sp$ hybridized carbon) are acidic and react with strong bases like soda amide $(NaNH_2)$ to form sodium acetylides.$CH_3-CH_2-C \equiv CH$ $(But-1-yne)$ is a terminal alkyne,so it reacts with $NaNH_2$:$CH_3-CH_2-C \equiv CH + NaNH_2 \rightarrow CH_3-CH_2-C \equiv CNa + NH_3$$CH_3-C \equiv C-CH_3$ $(But-2-yne)$ is a non-terminal (internal) alkyne. It lacks an acidic hydrogen on the $sp$ carbon,so it does not react with $NaNH_2$.Therefore,the two compounds are $But-1-yne$ and $But-2-yne$.

Two compounds with molecular formula $C_4H_6$ are available. If one of the compounds can react with soda amide $(NaNH_2)$ while the second cannot react with it,identify these two organic compounds.

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