Two capacitors $C_1$ and $C_2$ in a circuit are joined as shown in the figure. The potential of point $A$ is $V_1$ and that of $B$ is $V_2$. The potential of point $D$ will be
- A$\frac{1}{2}(V_1 + V_2)$
- B$\frac{C_2V_1 + C_1V_2}{C_1 + C_2}$
- C$\frac{C_1V_1 + C_2V_2}{C_1 + C_2}$
- D$\frac{C_2V_1 - C_1V_2}{C_1 + C_2}$
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