(C) When capacitors are connected in series,the charge $(Q)$ on each capacitor is the same.Let $C_1 = 1\,\mu F$ and $C_2 = 2\,\mu F$.The total potenti

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(C) When capacitors are connected in series,the charge $(Q)$ on each capacitor is the same.Let $C_1 = 1\,\mu F$ and $C_2 = 2\,\mu F$.The total potential difference is $V = V_1 + V_2 = 120\,V$.Since $Q = C_1 V_1 = C_2 V_2$,we have $1 \times V_1 = 2 \times V_2$,which implies $V_1 = 2V_2$.Substituting this into the total voltage equation: $2V_2 + V_2 = 120\,V$.$3V_2 = 120\,V$,so $V_2 = 40\,V$.Therefore,$V_1 = 2 \times 40\,V = 80\,V$.The potential difference across the $1\,\mu F$ capacitor is $80\,V$.

Class 12 Physics Electric Potential and Capacitance Equivalent Capacitance of Capacitor connected in Series and Parallel

Medium

Two condensers of capacities $1\,\mu F$ and $2\,\mu F$ are connected in series and the system is charged to $120\,V$. Then the potential difference $(P.D.)$ across the $1\,\mu F$ capacitor (in $volts$) will be

A
$40$
B
$60$
C
$80$
D
$120$

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Electric Potential and Capacitance

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Equivalent Capacitance of Capacitor connected in Series and Parallel

The effective capacitance between points $A$ and $B$ shown in the circuit is

MediumTS EAMCET 2023

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Three equal capacitors,each with capacitance $C$,are connected as shown in the figure. The equivalent capacitance between $A$ and $B$ is:

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Three capacitors of capacitances $C_1=2 \mu F$,$C_2=3 \mu F$ and $C_3=5 \mu F$ are connected in series. $A$ potential difference of $155 \ V$ is applied across the combination. Choose the correct option.

DifficultAP EAMCET 2020

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Three capacitors,each of value $1 \ \mu\text{F}$,are connected in such a way that the resultant capacitance is $1.5 \ \mu\text{F}$. Then:

Easy

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Five capacitors,each of capacitance $C$,are connected as shown in the figure. The ratio of the equivalent capacitance between $P$ and $R$ to the equivalent capacitance between $P$ and $Q$ is:

MediumAIIMS 2006

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Two condensers of capacities $1\,\mu F$ and $2\,\mu F$ are connected in series and the system is charged to $120\,V$. Then the potential difference $(P.D.)$ across the $1\,\mu F$ capacitor (in $volts$) will be

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