Two conducting wires of the same material,equ | vedclass

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(B) Let the resistance of each wire be $R$.When connected in series,the total resistance is $R_{S} = R + R = 2R$.The heat produced by the series combi

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It becomes half the heat produced by a single wire.

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(B) Let the resistance of each wire be $R$.When connected in series,the total resistance is $R_{S} = R + R = 2R$.The heat produced by the series combination is given by $H = \frac{V^{2}}{R_{S}} t = \frac{V^{2}}{2R} t$.The heat produced by an individual resistor (if connected alone to the same voltage source) is $H' = \frac{V^{2}}{R} t$.Comparing the two,we find $H = \frac{1}{2} \left( \frac{V^{2}}{R} t \right) = \frac{H'}{2}$.Thus,the heat produced by the series combination is half the heat produced by a single wire.

Sample	Resistivity $(\Omega \cdot m)$
$A$	$1.6 \times 10^{-8}$
$B$	$7.5 \times 10^{17}$
$C$	$44 \times 10^{-6}$

Two conducting wires of the same material,equal length,and equal diameter are connected in series. How does the heat produced by the combination of resistance change?

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