Two dice are thrown together. The probability | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) When two dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.Let $E$ be the event that at least one die shows the digit $6$

Vedclass · Accepted Answer

$\frac{11}{36}$

Vedclass · Answer

(A) When two dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.Let $E$ be the event that at least one die shows the digit $6$.The outcomes where at least one die shows $6$ are:$(1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1)$.Counting these outcomes,we find there are $11$ favorable outcomes.Therefore,the probability $P(E) = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{11}{36}$.

Two dice are thrown together. The probability that at least one will show its digit $6$ is

Similar Questions

$A$ basket contains $3$ blue and $4$ red balls. If $3$ balls are drawn at random from the basket,then what is the probability that all the $3$ are either blue or red?

Five-digit numbers are formed using the digits $1, 2, 3, 4, 5, 6$,and $8$. What is the probability that they have even digits at both the ends?

$A$ box contains $15$ black and $20$ white balls. What is the probability that when $2$ balls are selected,both are white?

An $URN$ contains $6$ blue,$4$ red,$3$ green and $2$ yellow marbles. If four marbles are picked at random,what is the probability that one is yellow,two are red and one is blue?

Let $0 < P(A) < 1$,$0 < P(B) < 1$ and $P(A \cup B) = P(A) + P(B) - P(A)P(B).$ Then

Vedclass Test Series

Exam Paper Generator

Online Exam Module