Two dielectric slabs having dielectric constants $K_1$ and $K_2$ of thicknesses $\frac{d}{4}$ and $\frac{3d}{4}$ are inserted between the plates of a capacitor as shown in the figure. The net capacitance between $A$ and $B$ is [where $\varepsilon_0$ is the permittivity of free space].

  • A
    $\frac{2 A \varepsilon_0}{d} \left[\frac{K_1 K_2}{3 K_1+K_2}\right]$
  • B
    $\frac{3 A \varepsilon_0}{d} \left[\frac{K_1+K_2}{K_1 K_2}\right]$
  • C
    $\frac{3 A \varepsilon_0}{2 d} \left[\frac{K_1+K_2}{K_1 K_2}\right]$
  • D
    $\frac{4 A \varepsilon_0}{d} \left[\frac{K_1 K_2}{3 K_1+K_2}\right]$

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