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(B) According to Faraday's second law of electrolysis,for cells connected in series,the mass of substances deposited is proportional to their equivale

Vedclass · Accepted Answer

$9.525$

Vedclass · Answer

(B) According to Faraday's second law of electrolysis,for cells connected in series,the mass of substances deposited is proportional to their equivalent weights: $\frac{W_{Cu}}{W_{Al}} = \frac{E_{Cu}}{E_{Al}}$.Equivalent weight of $Cu = \frac{	ext{Atomic mass of } Cu}{	ext{Valency factor}} = \frac{63.5}{2} = 31.75 \ g \ eq^{-1}$.Equivalent weight of $Al = \frac{	ext{Atomic mass of } Al}{	ext{Valency factor}} = \frac{27}{3} = 9 \ g \ eq^{-1}$.Given $W_{Al} = 2.7 \ g$.Substituting the values: $\frac{W_{Cu}}{2.7} = \frac{31.75}{9}$.$W_{Cu} = \frac{31.75 	imes 2.7}{9} = 31.75 	imes 0.3 = 9.525 \ g$.

Column $I$ (Reduction process)	Column $II$ (Charge required)
$(a)$ $1$ mol of $MnO_4^-$ to $Mn^{2+}$	$(p)$ $193000$ $C$
$(b)$ $1$ mol of $Cr_2O_7^{2-}$ to $Cr^{3+}$	$(q)$ $289500$ $C$
$(c)$ $1$ mol of $Sn^{4+}$ to $Sn^{2+}$	$(r)$ $482500$ $C$
$(d)$ $1$ mol of $Al^{3+}$ to $Al$	$(s)$ $579000$ $C$

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