Two different liquids of same mass are kept i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let $P$ be the rate of heat removal (power). Since heat is extracted at the same rate,$P$ is constant for both.The heat lost by a substance is giv

Vedclass · Accepted Answer

$C_{L1} > C_{L2}$ and $C_{S1} < C_{S2}$

Vedclass · Answer

(B) Let $P$ be the rate of heat removal (power). Since heat is extracted at the same rate,$P$ is constant for both.The heat lost by a substance is given by $dQ = m \cdot c \cdot dT$,where $m$ is the mass and $c$ is the specific heat.The rate of heat removal is $P = \frac{|dQ|}{dt} = m \cdot c \cdot \left| \frac{dT}{dt} ight|$.Thus,the magnitude of the slope of the $T-t$ graph is $\left| \frac{dT}{dt} ight| = \frac{P}{m \cdot c}$.Since $P$ and $m$ are constant,the slope is inversely proportional to the specific heat: $	ext{Slope} \propto \frac{1}{c}$.$1$. For the liquid state (the initial cooling phase): Looking at the graph,the slope of curve $1$ is smaller than the slope of curve $2$. Since $	ext{Slope} \propto \frac{1}{C_L}$,a smaller slope implies a larger specific heat. Therefore,$C_{L1} > C_{L2}$.$2$. For the solid state (the final cooling phase): Looking at the graph,the slope of curve $1$ is larger than the slope of curve $2$. Since $	ext{Slope} \propto \frac{1}{C_S}$,a larger slope implies a smaller specific heat. Therefore,$C_{S1} Thus,the correct option is $C_{L1} > C_{L2}$ and $C_{S1} < C_{S2}$.

Similar Questions

If two balls of the same metal weighing $5\, g$ and $10\, g$ strike a target with the same velocity,and the heat energy developed is used solely for raising their temperature,then the temperature rise will be higher:

$1 \ gm$ of ice at $0^o C$ is mixed with $1 \ gm$ of steam at $100^o C$. What will be the final temperature $(^o C)$?

Find the difference in temperature between the water at the top and the bottom of a $20 \ m$ high waterfall, assuming $10 \%$ of the energy of the fall is spent in heating the water. [Use specific heat capacity of water $= 4000 \ J \ kg^{-1} K^{-1}$ and $g = 10 \ m/s^2$]. (in $^{\circ} C$)

The variation of density of water with temperature is represented by the

Vedclass Test Series

Exam Paper Generator

Online Exam Module