Two diodes are connected in the following fas | vedclass

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(B) In the given circuit, the diodes are connected such that their cathodes are tied together at point $Q$, which is connected to a $+5 \,V$ supply th

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$AND$ gate

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(B) In the given circuit, the diodes are connected such that their cathodes are tied together at point $Q$, which is connected to a $+5 \,V$ supply through a resistor $R$.$1$. If both inputs $A$ and $B$ are at $0 \,V$ (low), both diodes are forward-biased. The potential at $Q$ is pulled down to approximately $0 \,V$ (low).$2$. If one input is at $0 \,V$ and the other is at $+5 \,V$, the diode connected to $0 \,V$ is forward-biased, pulling the potential at $Q$ down to approximately $0 \,V$ (low).$3$. If both inputs $A$ and $B$ are at $+5 \,V$ (high), both diodes are reverse-biased. No current flows through the diodes, and the potential at $Q$ is pulled up to $+5 \,V$ (high) by the supply through resistor $R$.Since the output $Q$ is high only when both inputs $A$ and $B$ are high, this circuit functions as an $AND$ gate.

Two diodes are connected in the following fashion. Provision is made to connect either $+5 \,V$ or ground $(0 \,V)$ to the points $A$ and $B$. The output $Q$ will act as

Similar Questions

The truth table given below is for ($A$ and $B$ are the inputs,$Y$ is the output).
$A$ $B$ $Y$
$0$ $0$ $1$
$0$ $1$ $1$
$1$ $0$ $1$
$1$ $1$ $0$

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