Two electric bulbs marked 25 W-220 V and 100 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) First,calculate the resistance and rated current capacity for each bulb.For the $25 W$ bulb: $R_1 = \frac{V^2}{P_1} = \frac{220^2}{25} = 1936 \Ome

Vedclass · Accepted Answer

$25 W$ bulb

Vedclass · Answer

(C) First,calculate the resistance and rated current capacity for each bulb.For the $25 W$ bulb: $R_1 = \frac{V^2}{P_1} = \frac{220^2}{25} = 1936 \Omega$. The rated current is $I_1 = \frac{P_1}{V} = \frac{25}{220} \approx 0.114 \ A$.For the $100 W$ bulb: $R_2 = \frac{V^2}{P_2} = \frac{220^2}{100} = 484 \Omega$. The rated current is $I_2 = \frac{P_2}{V} = \frac{100}{220} \approx 0.454 \ A$.When connected in series to a $440 \ V$ supply,the total resistance is $R_{eq} = R_1 + R_2 = 1936 + 484 = 2420 \ \Omega$.The current flowing through the series circuit is $I = \frac{V_{total}}{R_{eq}} = \frac{440}{2420} \approx 0.181 \ A$.Comparing the circuit current $I$ with the rated capacities: Since $I (0.181 \ A) > I_1 (0.114 \ A)$,the $25 \ W$ bulb will exceed its rated current capacity and fuse. Since $I (0.181 \ A) < I_2 (0.454 \ A)$,the $100 \ W$ bulb will remain safe.

Two electric bulbs marked $25 W-220 V$ and $100 W-220 V$ are connected in series to a $440 V$ supply. Which of the bulbs will fuse?

Similar Questions

$A$ resistor ${R_1}$ dissipates the power $P$ when connected to a certain generator. If the resistor ${R_2}$ is put in series with ${R_1}$,the power dissipated by ${R_1}$

For the given circuit diagram,if the dissipated electrical power is $150 \text{ W}$,find the value of resistance $R$. (in $\Omega$)

In the scenarios given below,a person is standing on a wooden plank. In which of the following options do they draw the most current when simultaneously touching:

What is the current $I$ (in $A$) flowing through the given circuit?

$A$ car has a fresh storage battery of emf $12 \, V$ and internal resistance $2 \times 10^{-2} \, \Omega$. If the starter motor draws a current of $80 \, A$, then the terminal voltage when the starter is $ON$ is: (in $V$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module