Two electric bulbs rated P_1 text{ watt}, V t | vedclass

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(A) The power rating of a bulb is given by $P = \frac{V^2}{R}$,where $V$ is the rated voltage and $R$ is the resistance of the bulb.For the two bulbs,

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$P_1 + P_2 	ext{ watt}$

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(A) The power rating of a bulb is given by $P = \frac{V^2}{R}$,where $V$ is the rated voltage and $R$ is the resistance of the bulb.For the two bulbs,the resistances are $R_1 = \frac{V^2}{P_1}$ and $R_2 = \frac{V^2}{P_2}$.When connected in parallel to a voltage source $V$,the total power $P_p$ consumed is the sum of the power consumed by each bulb.Since the voltage across each bulb remains $V$,the power consumed by each bulb is its rated power.Therefore,the total power $P_p = P_1 + P_2$.

Two electric bulbs rated $P_1 \text{ watt}, V \text{ volts}$ and $P_2 \text{ watt}, V \text{ volts}$ are connected in parallel and $V \text{ volts}$ are applied to the combination. The total power consumed will be:

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