Two equal drops are falling through air with a steady velocity of $5\, cm/s$. If two drops coalesce to form one drop,then the new terminal velocity will be:

  • A
    $5 \times (4)^{1/3}\, cm/s$
  • B
    $5\sqrt{2}\, cm/s$
  • C
    $\frac{5}{\sqrt{2}}\, cm/s$
  • D
    $10\, cm/s$

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