Two equal forces (P each) act at a point incl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnitude of the resultant $R$ of two vectors $A$ and $B$ inclined at an angle $	heta$ is given by the formula: $R = \sqrt{A^2 + B^2 + 2AB \c

Vedclass · Accepted Answer

$P$

Vedclass · Answer

(C) The magnitude of the resultant $R$ of two vectors $A$ and $B$ inclined at an angle $	heta$ is given by the formula: $R = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$ Given that the two forces are equal,$A = B = P$,and the angle between them is $	heta = 120^\circ$. Substituting these values into the formula: $R = \sqrt{P^2 + P^2 + 2(P)(P) \cos(120^\circ)}$ Since $\cos(120^\circ) = -1/2$: $R = \sqrt{2P^2 + 2P^2(-1/2)}$ $R = \sqrt{2P^2 - P^2}$ $R = \sqrt{P^2} = P$ Therefore,the magnitude of the resultant force is $P$.

Two equal forces ($P$ each) act at a point inclined to each other at an angle of $120^\circ$. The magnitude of their resultant is

Similar Questions

What is the minimum number of vectors of equal magnitude required to produce a zero resultant vector?

There are two force vectors,one of $5\, N$ and the other of $12\, N$. At what angle should the two vectors be added to get a resultant vector of $17\, N$,$7\, N$,and $13\, N$ respectively?

Three vectors each of magnitude $3 \sqrt{1.5}$ units are acting at a point. If the angle between any two vectors is $\frac{\pi}{3}$,then the magnitude of the resultant vector of the three vectors is

Write two properties of vector addition.

When $n$ vectors of different magnitudes are added,we get a null vector. Then the value of $n$ cannot be

Vedclass Test Series

Exam Paper Generator

Online Exam Module