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(A) The sensitivity $S$ of a galvanometer is defined as the deflection per unit current,given by $S = \frac{	heta}{I}$.Given that both galvanometers

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$S_{A} > S_{B}$

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(A) The sensitivity $S$ of a galvanometer is defined as the deflection per unit current,given by $S = \frac{	heta}{I}$.Given that both galvanometers produce the same deflection $	heta = 20$ divisions.For galvanometer $A$,$S_{A} = \frac{	heta}{I_{A}} = \frac{20}{4 \ mA} = 5 \ 	ext{div/mA}$.For galvanometer $B$,$S_{B} = \frac{	heta}{I_{B}} = \frac{20}{7 \ mA} \approx 2.86 \ 	ext{div/mA}$.Comparing the two,$S_{A} > S_{B}$.Alternatively,since $S \propto \frac{1}{I}$ for a constant deflection,$\frac{S_{A}}{S_{B}} = \frac{I_{B}}{I_{A}} = \frac{7}{4} = 1.75$.Thus,$S_{A} = 1.75 S_{B}$,which implies $S_{A} > S_{B}$.

Two galvanometers $A$ and $B$ require currents of $4 \ mA$ and $7 \ mA$,respectively,to produce the same deflection of $20$ divisions. If $S_{A}$ and $S_{B}$ are their sensitivities,respectively,then:

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