Two identical bar magnets are held perpendicular to each other with a certain separation,as shown below. The area around the magnets is divided into four zones. Given that there is a neutral point,it is located in:

$A$ bar magnet is placed in the north-south direction with its north pole pointing towards the geographic north. In which direction from the center of the magnet will the points of zero magnetic field (neutral points) be located?

The frequency of vibration in a vibration magnetometer of the combination of two bar magnets of magnetic moments $M_1$ and $M_2$ is $6 \ Hz$ when like poles are tied together and it is $2 \ Hz$ when the unlike poles are tied together, then the ratio $M_1: M_2$ is

$A$ short magnet oscillates with a time period $0.1 \, s$ at a place where the horizontal magnetic field is $24 \, \mu T$. $A$ downward current of $18 \, A$ is established in a vertical wire kept at a distance of $20 \, cm$ east of the magnet. The new time period of oscillations of the magnet is (in $s$)

To compare magnetic moments of two magnets by vibration magnetometer,the 'sum and difference method' is better because:

$A$ short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at $14 \; cm$ from the centre of the magnet. The earth's magnetic field at the place is $0.36 \; G$ and the angle of dip is zero. If the bar magnet is turned around by $180^o$,where will the new null points (in $cm$) be located?