(A) In circuit $A$,the diode is reverse-biased. Therefore,no current flows through the circuit. The capacitor $A$ remains fully charged. Thus,$Q_{A} =

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(A) In circuit $A$,the diode is reverse-biased. Therefore,no current flows through the circuit. The capacitor $A$ remains fully charged. Thus,$Q_{A} = CV$.In circuit $B$,the diode is forward-biased. The capacitor discharges through the resistor $R$. The charge on the capacitor at any time $t$ is given by $q(t) = Q_{0} e^{-\frac{t}{RC}}$,where $Q_{0} = CV$.At time $t = CR$,the charge $Q_{B}$ is:$Q_{B} = CV e^{-\frac{CR}{RC}} = CV e^{-1} = \frac{CV}{e}$.Therefore,$Q_{A} = CV$ and $Q_{B} = \frac{CV}{e}$.

Class 12 Physics Electric Potential and Capacitance Charging and Discharging of Capacitance and RC circuit (DC)

Medium

Two identical capacitors $A$ and $B$,charged to the same potential $V$,are connected in two different circuits as shown below at time $t=0$. If the charge on capacitors $A$ and $B$ at time $t=CR$ is $Q_{A}$ and $Q_{B}$ respectively,then (Here $e$ is the base of natural logarithm):

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A
$Q_{A}=VC, Q_{B}=\frac{VC}{e}$
B
$Q_{A}=\frac{CV}{2}, Q_{B}=\frac{VC}{e}$
C
$Q_{A}=VC, Q_{B}=CV$
D
$Q_{A}=\frac{VC}{e}, Q_{B}=\frac{CV}{2}$

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Class 12

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Electric Potential and Capacitance

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Charging and Discharging of Capacitance and RC circuit (DC)

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Two identical capacitors $A$ and $B$,charged to the same potential $V$,are connected in two different circuits as shown below at time $t=0$. If the charge on capacitors $A$ and $B$ at time $t=CR$ is $Q_{A}$ and $Q_{B}$ respectively,then (Here $e$ is the base of natural logarithm):

Similar Questions

In the circuit shown,the switch is shifted from position $1 \rightarrow 2$ at $t = 0$. The switch was initially in position $1$ for a long time. The graph between the charge on capacitor $C$ and time $t$ is:

What will be the current through the $200 \Omega$ resistor in the given circuit, a long time after the switch $K$ is closed?

In the $R-C$ circuit shown in the figure, the total energy of $3.6 \times 10^{-3} \ J$ is dissipated in the $10 \ \Omega$ resistor when the switch $S$ is closed. The initial charge on the capacitor is ..... $\mu C$.

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