Two identical capacitors $A$ and $B$ are connected in series to a battery of $E$.$M$.$F$. $E$. Capacitor $B$ contains a slab of dielectric constant $K$. $Q_A$ and $Q_B$ are the charges stored in $A$ and $B$. When the dielectric slab is removed,the corresponding charges are $Q_A^{\prime}$ and $Q_B^{\prime}$. Then:

• A
  $\frac{Q_A^{\prime}}{Q_A}=\frac{K}{2}$
• B
  $\frac{Q_B^{\prime}}{Q_B}=\frac{K+1}{2}$
• C
  $\frac{Q_A^{\prime}}{Q_A}=\frac{K+1}{K}$
• D
  $\frac{Q_B^{\prime}}{Q_B}=\frac{K+1}{2K}$