Two identical charged spheres of material den | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $m$ be the mass of each sphere and $V$ be its volume. The density of the sphere is $\rho = m/V$,so $m = V\rho$.In air,the forces acting on the

Vedclass · Accepted Answer

$\frac{\rho}{\rho-\sigma}$

Vedclass · Answer

(A) Let $m$ be the mass of each sphere and $V$ be its volume. The density of the sphere is $ho = m/V$,so $m = Vho$.In air,the forces acting on the sphere are tension $T$,weight $mg$,and electrostatic force $F_e = \frac{1}{4\pi\epsilon_0} \frac{q^2}{r^2}$.For equilibrium,$	an(	heta/2) = \frac{F_e}{mg} = \frac{q^2}{4\pi\epsilon_0 r^2 mg}$.In a liquid of density $\sigma$,the sphere experiences an upthrust $F_b = V\sigma g$. The effective weight is $mg' = mg - V\sigma g = Vg(ho - \sigma)$.The electrostatic force in the liquid is $F_e' = \frac{F_e}{K}$.Since the angle $	heta$ remains the same,$	an(	heta/2) = \frac{F_e'}{mg'} = \frac{F_e}{K Vg(ho - \sigma)}$.Equating the two expressions for $	an(	heta/2)$:$\frac{F_e}{Vho g} = \frac{F_e}{K Vg(ho - \sigma)}$.Solving for $K$,we get $K = \frac{ho}{ho - \sigma}$.

Two identical charged spheres of material density $\rho$,suspended from the same point by inextensible strings of equal length,make an angle $\theta$ between the strings. When suspended in a liquid of density $\sigma$,the angle $\theta$ remains the same. The dielectric constant $K$ of the liquid is

Similar Questions

$A$ particle of mass $2\,g$ and charge $1\,\mu C$ is released from a distance of $1\,m$ from a fixed charge of $1\,mC$. What will be the velocity of the particle at a distance of $10\,m$ from the fixed charge (in $m/s$)?

$A$ charge $+q$ is situated at a distance $d$ away from both the sides of a grounded conducting $L$-shaped sheet as shown in the figure. The force acting on the charge $+q$ is:

An uncharged metal sphere is placed between two charged parallel plates. The pattern of the electric field lines will be:

Four charges are arranged at the corners of a square $ABCD$,as shown. The force on a $+ve$ charge kept at the centre of the square is

Vedclass Test Series

Exam Paper Generator

Online Exam Module