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(C) Let the radius of each small drop be $r$. The capacitance of a spherical drop is given by $C = 4\pi\epsilon_0 r$.When two identical drops of radiu

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less than $2C$ but greater than $C$

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(C) Let the radius of each small drop be $r$. The capacitance of a spherical drop is given by $C = 4\pi\epsilon_0 r$.When two identical drops of radius $r$ merge to form a larger drop of radius $R$, the volume remains conserved.So, $\frac{4}{3}\pi R^3 = 2 	imes \frac{4}{3}\pi r^3$, which gives $R = 2^{1/3}r$.The capacitance of the new large drop is $C' = 4\pi\epsilon_0 R$.Substituting $R = 2^{1/3}r$, we get $C' = 4\pi\epsilon_0 (2^{1/3}r) = 2^{1/3}C$.Since $1 < 2^{1/3} < 2$, the resultant capacitance $C'$ is less than $2C$ but greater than $C$.

Two identical charged spherical drops, each of capacitance $C$, merge to form a single drop. The resultant capacitance is:

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