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(C) The capacitance of a spherical drop of radius $r$ is given by $C = 4\pi\epsilon_0 r$.When $n$ identical drops of radius $r$ merge to form a single

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Less than $2C$ but greater than $C$

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(C) The capacitance of a spherical drop of radius $r$ is given by $C = 4\pi\epsilon_0 r$.When $n$ identical drops of radius $r$ merge to form a single drop of radius $R$, the volume remains conserved.So, $n 	imes (\frac{4}{3}\pi r^3) = \frac{4}{3}\pi R^3$, which implies $R = n^{1/3}r$.The capacitance of the new drop is $C' = 4\pi\epsilon_0 R = 4\pi\epsilon_0 (n^{1/3}r) = n^{1/3}C$.For $n = 2$, the new capacitance is $C' = 2^{1/3}C$.Since $1 < 2^{1/3} < 2$, the resultant capacitance $C'$ is less than $2C$ but greater than $C$.

Two identical charged spherical drops, each of capacitance $C$, merge to form a single drop. The resultant capacitance is

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