Two identical thin bar magnets,each of length | vedclass

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(D) The magnetic dipole moment of each bar magnet is given by $M = m l$.Since the two magnets are placed at a right angle to each other,their magnetic

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$\sqrt{2} ml$

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(D) The magnetic dipole moment of each bar magnet is given by $M = m l$.Since the two magnets are placed at a right angle to each other,their magnetic moment vectors $\vec{M_1}$ and $\vec{M_2}$ are also perpendicular to each other.The magnitude of each magnetic moment is $M_1 = M_2 = M = ml$.The net magnetic moment of the system is the vector sum of the individual magnetic moments:$M_{net} = \sqrt{M_1^2 + M_2^2 + 2 M_1 M_2 \cos 90^{\circ}}$Since $\cos 90^{\circ} = 0$,this simplifies to:$M_{net} = \sqrt{M_1^2 + M_2^2} = \sqrt{M^2 + M^2} = \sqrt{2M^2} = M \sqrt{2}$Substituting $M = ml$,we get:$M_{net} = \sqrt{2} ml$

Two identical thin bar magnets,each of length $l$ and pole strength $m$,are placed at a right angle to each other with the north pole of one touching the south pole of the other. The magnetic moment of the system is

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