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(A) Given:Charge on each sphere, $q = 6 	imes 10^{-7} \,C$.Distance between the centres, $r = 60 \,cm = 0.6 \,m$.According to Coulomb's Law, the elec

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$9 	imes 10^{-3} \,N$

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(A) Given:Charge on each sphere, $q = 6 	imes 10^{-7} \,C$.Distance between the centres, $r = 60 \,cm = 0.6 \,m$.According to Coulomb's Law, the electrostatic force $F$ is given by:$F = \frac{1}{4 \pi \varepsilon_0} \frac{q_1 q_2}{r^2}$Since $q_1 = q_2 = q = 6 	imes 10^{-7} \,C$ and $\frac{1}{4 \pi \varepsilon_0} = 9 	imes 10^9 \,N \cdot m^2/C^2$:$F = \frac{(9 	imes 10^9) 	imes (6 	imes 10^{-7}) 	imes (6 	imes 10^{-7})}{(0.6)^2}$$F = \frac{9 	imes 10^9 	imes 36 	imes 10^{-14}}{0.36}$$F = \frac{324 	imes 10^{-5}}{0.36}$$F = 900 	imes 10^{-5} \,N = 9 	imes 10^{-3} \,N$.

Two insulated charged metallic spheres $P$ and $Q$ of negligible radii have their centres separated by a distance of $60 \,cm$. The mutual force of electrostatic repulsion, if the charge on each is $6 \times 10^{-7} \,C$, is

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