Two light waves of same intensity superpose a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given that the intensity of both waves is the same,let $I_1 = I_2 = I_0$.The phase difference between the waves is $\Delta \phi = \pi/3$.The formu

Vedclass · Accepted Answer

$3I_0$

Vedclass · Answer

(C) Given that the intensity of both waves is the same,let $I_1 = I_2 = I_0$.The phase difference between the waves is $\Delta \phi = \pi/3$.The formula for the resultant intensity $I_R$ of two superposing waves is given by:$I_R = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos(\Delta \phi)$Substituting the given values into the formula:$I_R = I_0 + I_0 + 2\sqrt{I_0 \cdot I_0} \cos(\pi/3)$Since $\cos(\pi/3) = 1/2$,we get:$I_R = 2I_0 + 2I_0(1/2)$$I_R = 2I_0 + I_0 = 3I_0$Therefore,the resultant intensity at point $P$ is $3I_0$.

Two light waves of same intensity superpose at point $P$ with a phase difference of $\pi/3$. The resultant intensity at point $P$ will be?

Similar Questions

Two identical light waves having phase difference $\phi$ propagate in the same direction. When they superpose,the intensity of the resultant wave is proportional to:

Write down the principle of superposition and what is interference? Write down its types.

The phenomenon of interference is shown by

In the phenomenon of interference,energy.......

If the wavelength of light is $4000 \text{ Å}$, then the number of waves in $1 \text{ mm}$ length will be . . . . . . -

Vedclass Test Series

Exam Paper Generator

Online Exam Module