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(C) The magnetic field $B$ at a distance $r$ from a long straight current-carrying conductor is given by $B = \frac{\mu_0 I}{2 \pi r}$.Let the two con

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(C) The magnetic field $B$ at a distance $r$ from a long straight current-carrying conductor is given by $B = \frac{\mu_0 I}{2 \pi r}$.Let the two conductors be placed at a distance $d = 10 	ext{ cm} = 0.1 	ext{ m}$.At the midpoint,the distance from each conductor is $r = \frac{d}{2} = 0.05 	ext{ m}$.For the first conductor,the magnetic field $B_1$ at the midpoint is directed into the plane (using the right-hand thumb rule).For the second conductor,the magnetic field $B_2$ at the midpoint is directed out of the plane.Since the currents are equal $(I_1 = I_2 = 3 	ext{ A})$ and the distances are equal,the magnitudes of the magnetic fields are equal: $B_1 = B_2 = \frac{\mu_0 I}{2 \pi r}$.Since the fields are equal in magnitude and opposite in direction,the net magnetic field $B_{net} = B_1 - B_2 = 0$.

Two long straight parallel conductors $10 \text{ cm}$ apart,carry equal currents of magnitude $3 \text{ A}$ in the same direction. Then,the magnetic induction at a point midway between them is

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